Retornar e receber Exceptions utilizando ajax - java/jquery

<script src="jquery-1.7.1.js" type="text/javascript"></script>
     <script>
         $(document).ready(function () {
             $("#Save").click(function () {
                 $.ajax({
                     url: 'http://localhost:3413/api/person',
                     type: 'POST',
                     dataType: 'json',
                     success: function (data, textStatus, xhr) {
                         console.log(xhr);
                     },
                     error: function (xhr, textStatus, errorThrown) {
                         console.log(textStatus);
                     }
                 });
 
 
             });
         });
    </script>

public class personController : ApiController
    {
        [HttpPost]
        public void PostAction()
        {
            try
            {
                int zero = 0;
                int a = 100 / zero;
            }
            catch
            {
                var resp = new HttpResponseMessage(HttpStatusCode.ExpectationFailed)
                {
                    ReasonPhrase = "Devide by 0 Exception"
                };
                throw new HttpResponseException(resp);
            }
        }
 
    }