Transformando XML em HTML utilizando XSLT
Veja nesta dica um simples código de utilização do XSLT.
[arquivo.xml]
<?xml version="1.0"?>
<howto>
<topic>
<title>Java</title>
<url>http://www.devmedia/javahowto.htm</url>
</topic>
<topic>
<title>PowerBuilder</title>
<url>http://www.devmedia/pbhowto.htm</url>
</topic>
<topic>
<title>Javascript</title>
<url>http://www.devmedia/jshowto.htm</url>
</topic>
<topic>
<title>VBScript</title>
<url>http://www.devmedia/vbshowto.htm</url>
</topic>
</howto>
[arquivo.xsl]
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"version="1.0">
<xsl:template match="/">
<html>
<head><title>HowTo</title></head>
<body>
<table border="1">
<tr>
<th>Title</th>
<th>URL</th>
</tr>
<xsl:for-each select="howto/topic">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="url"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
[HowToXSLT.java]
// jdk 1.4.1
import javax.xml.transform.*;
import java.net.*;
import java.io.*;
public class HowToXSLT {public static void main(String[] args) {
try {
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer(
new javax.xml.transform.stream.StreamSource("arquivo.xsl"));
transformer.transform(
new javax.xml.transform.stream.StreamSource("arquivo.xml"),
new javax.xml.transform.stream.StreamResult(
new FileOutputStream("arquivo.html")));
} catch (Exception e) {
e.printStackTrace( );
}
}
}
